What is the output of the following code snippet?
var x = 5;
function foo() {
console.log(x);
}
function bar() {
var x = 10;
foo();
}
bar();
a)
0
b)
undefined
c)
5
d)
ReferenceError
Correct answer is option 'C'. Can you explain this answer?

Question

What is the output of the following code snippet?
var x = 5;

function foo() {
console.log(x);
}

function bar() {
var x = 10;
foo();
}

bar();

a)
0
b)
undefined
c)
5
d)
ReferenceError

Correct answer is option 'C'. Can you explain this answer?

Answer

The function foo has access to the global variable x, which is 5. When the foo function is called from the bar function, it logs the value of x, which is 5.

Answer

Output Explanation:

When the code is executed, the output will be:

5

Explanation:

The code snippet provided defines two functions: `foo` and `bar`.

Inside `foo` function, it logs the value of `x` using `console.log(x)`.

Inside `bar` function, a new variable `x` is declared and assigned the value 10 using `var x = 10`.

Then, the `foo` function is called within the `bar` function using `foo()`.

Since there is no `x` variable declared within the `foo` function, it looks for the variable in the surrounding scope, which is the global scope in this case.

In the global scope, a variable `x` is declared and assigned the value 5 using `var x = 5`.

So, when `foo` is called within `bar`, it logs the value of `x` from the global scope, which is 5.

Therefore, the output of the code will be `5`.

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